1 and 2 both go into -270, and they add up to 3.
Answer:
C(1,3) and D(1,4).
Step-by-step explanation:
The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of this quadrilateral ABCD intersect at E (2,5).
Recall that, the diagonals of a parallelogram bisects each other.
This means that; E(2,5) is the midpoint of each diagonal.
Let C and D have coordinates C(m,n) and D(s,t)
Using the midpoint rule:
The midpoint of AC is
This implies that;
The midpoint of BD is
This implies that;
Therefore the coordinates of C are (1,3) and D(1,4).
Answer:
8√0.2
Step-by-step explanation:
using Pythagoras Therom
(68)^2 = (60)^2 + (x)^2
4624 = 3600 + x^2
4624/3600 = x^2
1.28 = x^2
√1.28 = x
x = 8√0.02