Answer:
it would be B.
Step-by-step explanation:
if you do 4x+20=3x
then you solve x by simplifying both sides of the equation and isolate the variable.
Answer:
6xy²z^4
Step-by-step explanation:
![\sqrt[3]{216x^3y^6z^12}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E3y%5E6z%5E12%7D)
= ∛(6³)(x³)(y³)(y³)(z³)(z³)(z³)(z³) = 6x·y·y·z·z·z·z = 6xy²z^4
The final point should end up at (-11,-4)
Let,
Lee’s class size = L
Fred’s class size = F
We are told that Lee’s fifth-grade class has 1.0 times as
many students as Fred’s
Therefore, L = 1F
L = F
Question A. If there are a total of 60 students, how many
students does Fred’s class have?
Total number of students = 60
L + F = 60
Since L = F
L + F = F + F + 60
F + F = 60
2F = 60
F = 60/2
F = 30
Therefore, if there are a total of 60 students, Fred’s class
has 30 students.
QUESTION B. If there are a total of 60 students, how many
students does Lee’s class have?
Total number of students = 60
L + F = 60
Since L = F
L + F = L + L + 60
L + L = 60
2L = 60
L = 60/2
L = 30
Therefore, if there are a total of 60 students, Lee’s class
has 30 students.
The area of the paper used to wrap the gift is 3 3/4 square feet
<h3>How to determine the total area?</h3>
The dimension is given as:
1 1/4 by 3
The area is the product of the dimensions.
So, we have
Area = 1 1/4 * 3
Express as an improper fraction
Area = 5/4 * 3
Evaluate
Area = 15/4
Rewrite as:
Area = 3 3/4
Hence, the area of the paper used to wrap the gift is 3 3/4 square feet
Read more about areas at:
brainly.com/question/24487155
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