Suppose that the proportion of the white crest alleles (r) is given by w and that of the Red crest allele (R) is given by p. We have that p+w=1. The probability that an individual has 2 r alleles is given by w*w since for each allele position the probability is w. Only these individuals have a White phenotype. Hence, we get that w^2=

; the right hand side is the proportion of white birds in the total population. Doing the calculations, this yields that w=0.37. From this, we calculate that p=0.63. The possible ways we have heterozygous individuals are the combinations Rr and rR. The probability for each of those is p*w. Thus, the total probability is 2pw. This is equal to 0.466=0.47. This is the fraction of the future population that is going to be heterozygous assuming the conditions of the Handy-Weinberg equilibrium like random reproductive matching etc.
Thymine has a methyl group and is better suited for the storage property of the DNA molecule as it is far more stable compared to Uracil.
RNA contain Uracil instead of thymine so as to make differentiation of RNA molecule from DNA molecules easier.
Answer:
They have contributed same allele for straight hair.
Explanation:
There are two conditions homozygous and heterozygous. In homozygous conditions both the allele of a particular gene is same in an offspring which means the offspring got two same alleles from its parent for a particular gene and if an offspring is heterozygous for a gene that suggests that the parent has contributed two different alleles for that gene in the offspring.
So If Micah is homozygous for straight hair then it can be concluded that his parents have contributed two same alleles for straight hair genes.
Answer:
12. In our somatic (body) cells, we have 2N chromosomes, but in our sex cells (sperm & eggs), we have half the number of chromosomes, which is N chromosomes
Explanation: