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rosijanka [135]
3 years ago
14

What is shear stress​

Physics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

T=F/A

Explanation:

T= shear stress

F=applied force

A=cross sectional area

shear stress, force tending to cause deformation of material by slippage along a plane or planes parallel to the imposed stress, the resultant shear is of a great importance in nature, being intimately related to the downslope movement of earth materials and earthquakes.

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A proton moves at a speed of 1,140 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.78 T. If the proto
Yakvenalex [24]

Answer:

1.42×10⁻¹⁶ N.

Explanation:

The force on a charge moving in a magnetic field is given as

F = qBvsin∅..................... Equation 1

Where F = Force on the charge, q = charge, B = Magnetic Field, v = speed, ∅ = angle between the magnetic field and the speed

Given: B = 0.78 T,  v = 1140 m/s, ∅ = 90° ( Perpendicular) q = 1.60 × 10⁻¹⁹ C.

Substitute into equation 1

F = 0.78(1140)(1.60 × 10⁻¹⁹)sin90°

F = 1.42×10⁻¹⁶ N.

Hence the force on the charge = 1.42×10⁻¹⁶ N.

3 0
3 years ago
An object is 27.0 cm from a concave mirror of focal length 15.0 cm. find the image distance.
pantera1 [17]

The distance of the Image will be -33.75 cm

A concave mirror has an inward-curving reflecting surface that faces away from the light source. Unlike convex mirrors, a concave mirror's image forms a variety of images based on the object's proximity to the mirror.

Given that, an object placed 27 cm from a concave mirror having the focal length of 15 cm

We have to find distance of the Image

Using Mirror Formula:

1/f = 1/v + 1/u

Where,

f = focal length

v =  Image distance from the mirror

u = object distance from the mirror (concave)

Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.

1/(-15) = 1/v + 1/(-27)

1/(-15) = 1/v - (1/27)

1/v = -0.029

v = -33.75 cm

Therefore the distance of the Image will be -33.75 cm

Learn more about concave mirror here:

brainly.com/question/9816370

#SPJ10

8 0
2 years ago
A 40kg rock is perched atop a cliff that is 50 m high. What is it’s potential energy?
LekaFEV [45]
Potential energy, is energy due to its position.

Given: Mass m = 40 Kg;  Height h = 50 m

Required: Potential energy P.E = ?

Formula:  P.E = mgh   P.E = (40 Kg)(9.8 m/s²)(50 m)

                P.E = 19,600 J
4 0
4 years ago
Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
4 years ago
Which of these is an effect of space travel?
Bess [88]
The answers are 'muscle shrinkage' and 'decreased muscle cavity'. This is why unhealthy astronauts cannot go to space because it can be detrimental to their health.
8 0
3 years ago
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