Answer:
1.42×10⁻¹⁶ N.
Explanation:
The force on a charge moving in a magnetic field is given as
F = qBvsin∅..................... Equation 1
Where F = Force on the charge, q = charge, B = Magnetic Field, v = speed, ∅ = angle between the magnetic field and the speed
Given: B = 0.78 T, v = 1140 m/s, ∅ = 90° ( Perpendicular) q = 1.60 × 10⁻¹⁹ C.
Substitute into equation 1
F = 0.78(1140)(1.60 × 10⁻¹⁹)sin90°
F = 1.42×10⁻¹⁶ N.
Hence the force on the charge = 1.42×10⁻¹⁶ N.
