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zvonat [6]
3 years ago
10

Need help asap

Physics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

a=(v-u)÷t

a= (12-8)÷4

a= 4÷4

a= 1m/s²

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The speed limit sign in indiana reads 60 miles per hour. convert these units to meters per second
cluponka [151]

Answer:

26.822 m/s

Explanation:

60 mi/hr  *  5280 ft/mile *  1 hr / 3600 sec  *  12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>

3 0
1 year ago
identify each type of radiation as ionizing or non-ionizing. remember that ionizing radiation deposits enough energy when absorb
Tju [1.3M]

According to the definition given, non-ionizing means using microwaves on a substance without causing charged ions to form by removing electrons from atoms.

<h3>What kind of energy exist?</h3>

The six primary forms of energy are chemical, electromechanical, photonic, muscular, geothermal, and nuclear fuel. Other research may focus on other forms including electrochemical, psychological, electromagnetic, and others.

<h3>Why is energy such a big deal?</h3>

Energy is a crucial part of our everyday life despite being just a basic human need. The buildings that people have constructed are heated and cooled by energy. Energy is needed to do things like lift your finger, get out of bed, or even merely go along the main corridor.

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8 0
9 months ago
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
Please help!?!?!?!?!?!?!
adoni [48]

Answer:

D

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5 0
3 years ago
If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

E = \frac{1}{2}kx^{2}           .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

8 = \frac{1}{2}\timesk\times k \times(0.02)^{2}

k = 4 x 10⁴ N/m

Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).

Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

E = ( 72 - 8 ) J = 64 J

7 0
3 years ago
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