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uranmaximum [27]
2 years ago
9

An airplane is located at position (6,7,5) at noon and is traveling with velocity 400????+500????−???? kilometers per hour. The

pilot spots an airport at position (26,32,0).
(a) At what time will the plane pass directly over the airport? (Assume that the plane is flying over flat ground and that the vector k points straight up.)
(b) How high above the airport will the plane be when it passes?
Mathematics
1 answer:
Trava [24]2 years ago
3 0

Answer:

hahaahahahaaha thats easy

l

  1. haha hahahaha plane will crash
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The midpoint of AB is M(-5, -2). If the coordinates of A are (-3,4), what are
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3 years ago
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Ryan is 4 1/2 ft. tall. He is 3 in. taller than his sister Lizzie. She is 3/4 of a foot taller than her sister Emma. How tall is
77julia77 [94]

Answer:

3\frac{1}{12} ft tall

Step-by-step explanation:

We must follow the indications:

Ryan is 4 1/2 ft. tall.

Ryan = 4\frac{1}{12} ft

He is 3 in. taller than his sister Lizzie. to find how tall is Lizzie we need to substract 3 inches from the height of Ryan, but we can only substract the quantities if they are in the same units.

Thus we convert the 3 inches to feet, since we 1 feet = 12 inches:

\frac{1}{4} feet=3inches

so the height of lizzie:

4\frac{1}{12}ft-\frac{1}{4}ft\\  \\

we convert the first mixed number to fraction by multiplying 4 by 12 and adding the numerator 1:

4\frac{1}{12}=\frac{4*12+1}{12}=\frac{49}{12}

the subtraction becomes:

\frac{49}{12}ft-\frac{1}{4}ft\\  \\=\frac{49*4-12*1}{12*4}\\ \\=\frac{196-12}{48}\\\\=\frac{184}{48}\\ \\=\frac{46}{12} \\

=\frac{23}{6}

Lizzie is 23/6 ft tall.

She is 3/4 of a foot taller than her sister Emma, thus we must substract 3/4 from the height of Lizzie to find the height of Emma:

\frac{23}{6}ft-\frac{3}{4}ft\\  \\=\frac{23*4-6*3}{6*4}\\ \\=\frac{92-18}{24}\\ \\=\frac{74}{24}\\ \\=\frac{37}{12}\\ \\=3\frac{1}{12}

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4 0
2 years ago
What is the surface area of the triangular prism shown below<br> ???
Cerrena [4.2K]

<u>Given</u>:

Given that the base of the triangle is 4 cm.

The height of the triangle is 3 cm.

The height of the prism is 8 cm.

The other side of the triangle is 5 cm.

We need to determine the surface area of the triangular prism.

<u>Surface area of the triangular prism:</u>

The surface area of the triangular prism can be determined using the formula,

SA=bh+(s_1+s_2+s_3)H

where b is the base of the triangle,

h is the height of the triangle,

s₁, s₂, s₃ are the side lengths of the triangle and

H is the height of the prism.

Substituting b = 4, h = 3, s₁ = 4, s₂ = 3, s₃ = 5 and H = 8, we get;

SA=(4)(3)+(4+3+5)(8)

SA=12+(12)(8)

SA=12+96

SA=108 \ cm^2

Thus, the surface area of the triangular prism is 108 square cm.

5 0
3 years ago
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