Answer:
Percent yield = 94.5%
Explanation:
Given data:
Number of moles of hydrogen = 4.55 mol
Mass of ammonia recovered = 48.7 g
Percent yield of ammonia = ?
Solution:
Chemical equation:
N₂+ 3H₂ → 2NH₃
Now we will compare the moles of ammonia and hydrogen.
H₂ : NH₃
3 : 2
4.55 : 2/3×4.55 = 3.03 mol
Theoretical yield of ammonia:
Mass = number of moles × molar mass
Mass = 3.03 mol × 17 g/mol
Mass = 51.51 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (48.7 g/ 51.51 g) × 100
Percent yield = 0.945 × 100
Percent yield = 94.5%
The answer is c. Because it’s breaking things down
Total density of filled ball with hydrogen gas:
The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.
Density of hydrogen gas =
Mass of the hydrogen gas :
Learn more about Mass and Density here:
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It would be Neon because most abondent gas are nitrogoen, oxygen and Argon .