Molecules may be similar or different on the basis of size, shape, structure and chemical composition.
<h2>Similarities and differences</h2>
Two molecules can be considered similar or different on the basis of size, shape, structure and chemical composition. The molecules in the two proposed systems are consider the same when they are similar in size, shapes, structure and chemical composition.
While on the other hand, the molecules is considered different when they have different structure and chemical composition so we can say that molecules may be similar or different on the basis of size, shape, structure and chemical composition.
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To figure this out, you need to figure out how many molecules of mgso4 you have.
If you have 1.04 moles of MgSO4, you have that many moles times avogadro's number (6.022*10^23 molecules/mole).
1.04 moles MgSO4 * (6.022*10^23 molecules MgSO4)/1 mole MgSO4 =
6.263 *10^23 molecules MgSO4
Next, there are 4 oxygen atoms per molecule of MgSO4, so we multiply the number of molecules of MgSO4 by 4 to get the number of oxygen atoms.
6.263 *10^23 molecules MgSO4 * (4 oxygen atoms/1 MgSO4 molecule) = 2.51 * 10^24 oxygen atoms in 1.04 moles of MgSO4
Answer:
Deposition
Explanation:
It’s breaking down the rock :]
The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.
The mass of NaOH is 45 g
The molar mass of NaOH = 40 g/mol
The moles of NaOH = mass / molar mass
= 45 / 40
= 1.125
Thus, 1.125 mol NaOH is available
3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl
3 mol of NaOH react with 1 mol of FeCl₃
1.125 moles of NaOH will react with x moles of FeCl₃
x = 1.125 / 3
x = 0.375 mol
0.375 mol FeCl₃ can take part in reaction
The molar mass of FeCl₃ is 162 g/mol
The mass of FeCl₃ = moles × mass
= 0.375 × 162
= 60.75 g
Thus, the amount of FeCl₃, which can be consumed is 60.75 g
Answer:
See Explanation
Explanation:
moles of NH₃ = 11.9g/17.03 g/mol = 0.699 mole
moles of CN₂OH₄ = 1/2(0.699) mole =0.349 mole
Theoretical yield of CN₂OH₄ = (0.349 mole)(60 g/mole) = 20.963 grams
%Yield = Actual Yield/Theoretical Yield x 100%
= 18.5g/20.963g x 100% = 88.25%
