Answer:
5.85 gm.
Explanation:
We know that,
Normality =<u> Molarity × Molecular </u><u>weight</u>
Equivalent weight
Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5
Normality of NaCl= molarity=2
Now,
Normality= <u>weight</u><u> </u><u>in</u><u> </u><u>gram</u><u> </u><u>×</u><u>1000</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>
Volume ×equivalent weight
Weight in gram is given by,
<u>=</u><u>Normality × Volume × equivalent </u><u>weight</u>
1000
= <u>2× 50 × 58.</u><u>5</u>
1000
=5.85 gm.
32.) 55.6 mL HCl
33.) 0. 128 M
Answer:
(A) An investor will exercise the option to put the bond if yields rise significantly
Explanation:
A put option on the bond is a mechanism to allow the buyer of the bond the ability to compel the lender to repay the principal on the bond. The put option offers the buyer of the bond the ability to collect the principal of the bond anytime they choose until maturity for any purpose.
Recall that once the price drops (that is, the yield increases), put options are exercised. If the yield significantly increased, the put choice on a municipal bond is executed.
Answer:
(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol
(b)The freezing point for the aqueous solution is 
C
Explanation:
The osmotic pressure (π) is given by the following equation:
= Concentration of solution
R = universal gas constant = 62.364 
T = temperature
Weight of solute = w = 10.0 mg
Let the molecular weight of the solute be m g/mol.
Concentration = 
m = 18220.071g/mol
Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol
m is the molality of the solution.
m = 
mol/kg
= 
C
The freezing point for the aqueous solution is C
