Answer:
i think the answer will be b. the point where the ph corresponds to a solution of the conjugate acid (bh+) in water;
Explanation:
Answer:
Ag⁺, Ba²⁺,
Explanation:
We can solve this question using the <em>solubility rules:</em>
<em>When an Halide as Br- is added to a solution, the ions that can be precipitate are Ag⁺, Hg₂²⁺ and Pb²⁺.</em>
That means the first ion present is Ag⁺
<em>When sulfates, SO₄²⁻ are added, the ions that precipitates are: Ag⁺, Ca²⁺, Sr²⁺, Ba²⁺, Hg₂²⁺ and Pb²⁺</em>
The second ion present is Ba²⁺
Hydroxides of Cu²⁺ and Mn²⁺ are insolubles but as no precipitate are formed when the solution is strongly alkaline those ions are not present.
The Ksp of Mg(OH)2 in water is 1.8 x 10-<span>11. This means that in pure water, Mg(OH)2 has a solubility of:
</span>∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
<span>which is equal to
</span>1.65 x 10-4<span> mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL
If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
</span>1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL
In the apparatus of the electrochemical cell, the seawater is an example of an electrolyte.
<h3>What is an electrolyte?</h3>
An electrolyte is a component of the electrochemical cell that is a solution of solvent or water that contains dissolved ions.
The salts of sodium, chloride, and potassium are the main components of seawater and a great electrolyte.
Therefore seawater is an example of an electrolyte.
Learn more about electrolytes here:
brainly.com/question/2285692
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