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Romashka-Z-Leto [24]
3 years ago
9

Serial dilution problem: Six test tubes are placed in a rack. To each tube add 4 mL of saline solution. Now to the first tube ad

d 0.5 mL of concentrated protein (10 M) and mix well. Then transfer 1 mL of tube # 1 to tube # 2 and mix well. 1 mL of the contents of tube # 2 is then transferred to tube # 3, and the procedure is repeated for the remaining tubes. What is the dilution factor and molar concentration of protein in tube # 4? Show your answer by drawing 6 tubes and label them.

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

The dilution factor of protein in tube # 4 is 125. Molar concentration is 0.0088 M protein

Explanation:

The dilution factor indicates how many times is more concentrated a main solution in relationship with a diluted solution. In this case, the main solution is in tube #1. For calculating the dilution factor and molar concentration in tube #4 we need the main solution concentration which comes from next equation:

Initial volume * initial concentration = final volume * final concentration

0.5 mL * 10M = 5mL * final concentration

1.1 M = final concentration = main solution concentration

Applying the same equation for remain tubes we have 0.22 M for tube #2, 0.044 M for tube # 4 and 0.0088 for tube # 4.

Dilution factor = Main solution concentration/tube 4 concentration

Dilution factor = 1.1/0.0088 = 125

I hope my answer helps you

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Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

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1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

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\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

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Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

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7 0
2 years ago
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