Answer:
B. oxidation; reduction
Explanation:
A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.
1. This cell utilizes chemical reaction to generate electric.\
2. there two electrode anode and cathode
3. At Anode oxidation occurs
4. At cathode reduction occurs
5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.
- oxidation is the process in which there is loss of electrons
- Reduction is the process in which there is gain of electrons
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Based on above discussion
At anode oxidation takes place
At cathode reduction takes place.
Hence, correct option is B. oxidation; reduction
Answer:
The ability to decompose
Explanation:
A property is a chemical property when it changes the chemical structure of a substance after a reaction.
Density and color are both physical properties.
Even though melting point may seem like a chemical property, when something melts, only the physical state changes, and the chemical structure does not change, and therefore, is a physical property.
The ability to decompose is a chemical property. When something decomposes, the chemical structure of many molecules change, and therefore, is classified as a chemical property.
Balanced chemical reaction: Pb(NO₃)₂ (aq) + 2NaI(aq) → 2PbI₂(s) + 2NaNO₃(aq).
V(Pb(NO₃)₂) = 50 mL ÷ 1000 mL = 0.05 L, volume of solution.
c(Pb(NO₃)₂) = 0.1 mol/L; concentration of solution.
n(Pb(NO₃)₂) = c(Pb(NO₃)₂) · V(Pb(NO₃)₂).
n(Pb(NO₃)₂) = 0.1 mol/L · 0.05 L.
n(Pb(NO₃)₂) = 0.005 mol.
n(NaI) = c(NaI) · V(NaI).
n(NaI) = 0.1 mol/L · 0.05 L.
n(NaI) = 0.005 mol; amount of substance.
From chemical reaction: n(Pb(NO₃)₂) : n(NaI) = 1 : 2.
n(Pb(NO₃)₂) = 0.005 mol ÷ 2.
n(Pb(NO₃)₂) = 0.0025 mol; number of moles Pb(NO₃)₂ used.
n(NaI) = 0.005 mol; number of moles NaI used.
The limiting reagent is Pb(NO₃)₂.
n(PbI₂) = 0.005 mol.
m(PbI₂) = n(PbI₂) · M(PbI₂).
m(PbI₂) = 0.005 mol · 461 g/mol.
m(PbI₂) = 2.305 g; the theoretical yield of PbI₂.
Answer:
convert 250.0 mL in Liters :250. 0 / 1000 = 0,25 LDensity = 1.240 g/LMass
Explanation:
Answer:
3–ethyl–4–methylhexane.
Explanation:
To name the above compound, do the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached to the compound.
4. Give the substituent the lowest possible count.
5. Combine the above to name the compound.
Now, we shall name the compound given in the question above as follow:
1. The compound contains only single bond. Therefore, the compound belong to the alkane family.
2. The longest continuous carbon chain is 6 i.e hexane.
3. The substituent group attached are:
i. Methyl, CH3.
ii. Ethyl, CH2CH3.
4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,
Ethyl is located at carbon 3.
Methy is located at carbon 4.
5. Therefore, the name of the compound is:
3–ethyl–4–methylhexane.
