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ivolga24 [154]
2 years ago
9

Point (17,18) is located in quadrant​

Mathematics
2 answers:
Nadusha1986 [10]2 years ago
7 0

Answer:

25

Step-by-step explanation:

add 7+ to the quadrant to 18+

zysi [14]2 years ago
3 0

Answer:

Step-by-step explanation:

x and y both positive.

so it lies in first quadrant.

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Of 136 people visiting an art gallery, 17 bought paintings. What percent of the visitors bought a painting? Answer for crown :)
8_murik_8 [283]

Answer:

12.5%

Step-by-step explanation:

7 0
3 years ago
Find the net change in the value of the function between the given inputs. h(t) = t2 + 2; from −5 to 8
pashok25 [27]

Answer:

39

Step-by-step explanation:

Given the function :

h(t) = t² + 2

From t = 5 to t = 8

when, t = 5

h(5) = 5² + 2

h(5) = 25 + 2

h(t) at t = 5 ; equals 27

when, t = 8

h(5) = 8² + 2

h(5) = 64 + 2

h(t) at t = 8 ; equals 66

Net Change :

h(8). - h(5)

66 - 27 = 39

3 0
2 years ago
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eimsori [14]
I’m on the same question
3 0
3 years ago
The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor
Nataliya [291]

Answer:

Okapi 290 kg

Llama 160 kg


Step-by-step explanation:

Let weight of each llama be  l

Let weight of each okapi be  o


<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>

<em>l+o=450</em>

<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>

<em>3l-190=o</em>


Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160


Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

o=3l-190\\o=3(160)-190\\o=290

Each okapi weigh 290 kg

5 0
3 years ago
Question 2 (1 point) Lin knows there are 4 quarts in a gallon. She wants to convert 6 quarts to gallons, but she cannot decide i
elixir [45]

Answer:

multiply

Step-by-step explanation:

7 0
3 years ago
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