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ElenaW [278]
3 years ago
14

A student is conducting an experiment in which he adds an inhibitor to an enzyme-catalyzed reaction that contains alkaline phosp

hatase. When the student first adds the inhibitor, the reaction rate decreases, however, he can return the reaction rate to normal by adding a large quantity of substrate. What type of inhibitor is the student using, non-competitive or competitive?
Computers and Technology
1 answer:
Zigmanuir [339]3 years ago
7 0

Answer:

competitive

Explanation:

An inhibitor is a substance that hinders the action of an enzyme. An inhibitor may be competitive or non competitive.

A competitive inhibitor is an inhibitor that is very similar to the substrate hence it binds to the enzyme instead of the substrate. A noncompetitive inhibitor binds to a site that is different from the active site. This site is called an allosteric site.

If we look at the experiment described in the question, the reaction rate decreases upon addition of the inhibitor. This effect is reversed by adding a large quantity of substrate.

The implication of this observation is that the enzyme and the inhibitor compete for the active site on the substrate.

Hence the inhibitor is a competitive inhibitor.

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A ________ is a small message box that displays when the pointer is placed over a command button.
Aleonysh [2.5K]

An enhanced <u>ScreenTips</u> is a small message box that displays when the pointer is placed over a command button.

<h3>What are ScreenTips?</h3>

ScreenTips is known to be a term that connote a small windows that shows any kind of descriptive text if a person place the pointer on a command or on a control.

Note that Enhanced ScreenTips are found to be bigger windows that shows a lot of descriptive text than a ScreenTip.

Therefore, An enhanced <u>ScreenTips</u> is a small message box that displays when the pointer is placed over a command button.

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brainly.com/question/26677974

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6 0
2 years ago
A file named data.txt contains an unknown number of lines, each consisting of a single integer. Write some code that creates two
Damm [24]

Answer:

I am doing it with python.

Explanation:

nums = '9 -8 -7 -6 -5 -4 -2 0 1 5 9 6 7 4'

myfile = open('data.txt', 'w')

myfile.write(nums)

myfile.close()

myfile = open('data.txt', 'r')

num1 = (myfile.read())

num1 = num1.split()

print(num1)

print(type(num1))

for x in num1:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x>= 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

3 0
3 years ago
Read 2 more answers
Why would you use a custom filter?
Angelina_Jolie [31]

Answer:By specifying conditions, you can create custom filters that narrow down the data in the exact way that you want. You do this by building a filter. If you've ever queried data in a database, this will look familiar to you. Point to either Number Filters or Text Filters in the list.

Explanation:

5 0
3 years ago
Suppose you're choosing a university to attend, and you'd like to quantify how dissimilar any two universities are. You rate eac
Kazeer [188]

This question is incomplete. The complete question, answer & explanation for this question is given in the attachment below.

8 0
3 years ago
Define a function below called average_num_in_file. The function takes one argument: the name of a file full of numbers. Complet
Nookie1986 [14]

Answer:

  1. def average_num_in_file(fileName):
  2.    with open(fileName) as file:
  3.        rows = file.readlines()
  4.        sum = 0
  5.        count = 0
  6.        for x in rows:
  7.            sum += float(x)  
  8.            count += 1
  9.        average = sum / count  
  10.    return average  
  11. print(average_num_in_file("cans.txt"))

Explanation:

The solution code is written in Python 3.

Firstly create a function that take one parameter, fileName (Line 1).

Open the file stream and use readlines method to read the data from the file (Line 2-3). Create variable sum and count to tract the total of the number from text files and number of data from the file (Line 5-6). Use a for loop to loop over each row of the read data and add the current value of each row to sum and increment the count by one (Line 7-9).

After the loop, calculate the average (Line 11) and return the result (Line 12).

At last, we can test the function by passing the cans.txt as argument (Line 14).

7 0
4 years ago
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