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2 years ago

Jim drank 2/5 of his water bottle and John drank 3/10 of his water bottle. How much did the both boys drink?

Mathematics

1 answer:

suter [353]2 years ago

4 0

The boys drink 7/10 of a water bottle

1. Convert 2/5 into 4/10
2. Add 4/10 and 3/10

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2(6 – x) – (9x + 2) = 4 + 8(x – 4)

Crank

Answer:

1.526

Step-by-step explanation:

12-2x-9x-2 = 4+8x-32

-11x+10 = 8x-28

-19x = -29

x = 1.526

4 0

2 years ago

Which of the following describes the zeroes of the graph of f(x)= -x^5+9x^4-18x^3

Elina [12.6K]

Answer:

$-x^5+9x^4-18x^3=0\\-x^3(x^2-9x+18)=0\\-x^3(x-3)(x-6)=0\\\\\\\\x=0\\x=3\\x=6$

4 0

3 years ago

Which equation or function is linear?

zepelin [54]

9514 1404 393

Answer:

C. 2y = (2x-1)/4

Step-by-step explanation:

An equation is linear when the exponents of the variables are 1 and the sum of the exponents of the variables in any term is 1.

a) 3xy = 4 . . . . sum of exponents is 1+1=2

b) f(x) = 2/3(1 -x^2) . . . . exponent is 2

c) 2y = (2x -1)/4 . . . . all exponents are 1 (linear)

d) y = 3/(x+1) ⇒ xy +y = 3 . . . . sum of exponents is 1+1 = 2

8 0

3 years ago

Need help filling in the blanks: selling price using markup.

Xelga [282]

Answer:

Refer to the explanation.

Step-by-step explanation:

Let's take each one at a time.

To solve for the complement, we simply subtract our markup rate by 100%.

100% - 30% = 70%

Now to solve for the selling price, we use the formula

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{86.74}{0.70}$

Selling Price = $123.91

We do the same process with the first number.

100% - 40% = 60%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{220.00}{0.60}$

SellingPrice = $366.67

The same as the first two.

100% - 20% = 80%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{89.50}{0.80}$

SellingPrice = $111.88

Now to solve for the markup rate, we use the formula:

$MarkupRate=\dfrac{Markup}{SelingPrice}$

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.

Selling Price = $235.28

Cost = $199.99

Markup = $235.28 - $199.99

Markup = $35.29

Now the we know our markup, we can then solve for the markup rate using the formula.

$MarkupRate=\dfrac{Markup}{SelingPrice}$

$MarkupRate=\dfrac{35.29}{235.28}$

MarkupRate = 0.1499 x 100 = 14.99% or 15%

Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

Selling Price = $30.77

Complement = 65% or 0.65

This will then give us.

$30.77=\dfrac{Cost}{0.65}$

We multiple both sides of the equation by 0.65 to leave our cost alone.

30.77 x 0.65 = Cost

Cost = $20

4 0

2 years ago

Jose takes a job that offers a monthly starting salary of $2200 and guarantees him a monthly raise of $105 during his first year

vodka [1.7K]

Answer:

$3355

Step-by-step explanation:

Since the job offers starting salary of $2200 and monthly raise of $105 during his first year of training.

∴ a = 2200 and d = 105

Since the general form of A.P is,

a, a + d, a + 2d, a + 3d, ............. $a_{n}$

Where, $a_{n}$ is the last term of A.P or his monthly salary at the end of his training and n is the number of terms in a series.

So, the A.P is:

2200, 2200 + 105, 2200 + 2(105) ......... $a_{n}$

2200, 2305, 2410 ............ $a_{n}$

Since there is 12 month in a year therefore, n = 12.

$a_{n} = a + (n - 1) d\\$

. $a_{n}$ = 2200 + ( 12 - 1) × 105

= 2200 + 11 × 105

= 2200 + 1155

= 3355

∴ . $a_{n}$ = 3355

So the monthly salary of Jose at the end of his training is 3355$.

8 0

2 years ago