Jim drank 2/5 of his water bottle and John drank 3/10 of his water bottle. How much did the both boys drink?
1 answer:
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Answer:
The required function is:
The price for each feeder to maximize profit should be $13.
The maximum weekly profit is $147
Step-by-step explanation:
Consider the provided information.
Part (A)
The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.
Let x be the price per feeder.
Profit = Revenue - cost
So the profit per feeder is
If we increase then for every dollar increase, it loses 3 sales per week.
This can be written as:
Where x-10 represents the increase in price and 3 represents the decrease in sales per week.
Thus the profit will be:
Hence, the required function is:
Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?
The above function is a downward parabola so the maximum will occur at vertex.
The x coordinate of the vertex of parabola is:
Substitute a=-3, b=78 and c=-360 in above.
Hence, the price for each feeder to maximize profit should be $13.
Now substitute the value of x in
Hence, the maximum weekly profit is $147
Answer:
y = -1/8(x -1)² +4
Step-by-step explanation:
The equation of a parabola can be written from focus and directrix using the form ...
y = 1/(4p)(x -h)² +k
where p is the distance from vertex to focus, and (h, k) is the vertex.
The vertex-focus distance is half the distance from the directrix to the focus. Here, that is ...
p = (2 -6)/2 = -4/2 = -2
The vertex is halfway between the focus and directrix on the same vertical line, so has coordinates ...
(h, k) = ((1, 2) +(1, 6))/2 = (1, 4)
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Using these values of p and (h, k), we find the equation of the parabola to be ...
y = 1/(4(-2))(x -1)² +4
y = -1/8(x -1)² +4
_____
<em>Additional comment</em>
You can check the graph by considering the definition of a parabola: each point on the curve is equidistant from the focus and the directrix. This is easily verified for points on the horizontal and vertical lines through the focus. For example, point (5, 2) is 4 units from the focus, and 4 units from the directrix.
