Question

In a quiz-based program, there are three teams A, B and C. There is a total of five rounds in a game; 20 marks are given for each correct answer and -10 for each wrong answer. No marks are deducted for not attempting a question. Which team won the game, if:
a. Team A gave 3 correct and 2 wrong answers?

b. Team B gave 2 correct, 2 wrong answers and they didn’t attempt one question?

c. Team C gave 3 correct, and 1 wrong answer and they didn’t attempt one question?

Answer 1

From the given scenarios, the positions of winning of each team is; Team C came first, Team A came second and Team B came third

How to find probability of winning?

From the question, we can derive the following;

Marks gained by team A = 3 × 20 = 60 marks

Marks deducted = 2 × 10 = 20 marks

Hence;

Total marks for Team A = 60 - 20 = 40 marks

Marks gained by team B = 2 × 20 = 40 marks

Marks deducted = 2 × 10 = 20 marks

Hence, total marks of team B = 40 - 20 = 20 marks

Marks gained by team C = 3 × 20 = 60 marks

Marks deducted = 1 × 10 = 10 marks

Hence,  total marks of team C = 60 - 10 = 50 marks

Thus, we can conclude that;

Team C came first, Team A came second and Team B came third

Read more about Probability of winning at; brainly.com/question/24756209

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