Perimeter (p) of a rectangle = 2w+2l, or p/2 = w+l, 216 = 2w+2l, 108 = w+l
area (a) of a rectangle = l×w
So a = 2691 = l×w, l = 2691/w
p = 216 = 2w+2l, so 216 = 2w+2(2691/w)
216 = 2w + 5382/w
216 = 2w^2/w + 5382/w
216 = (2w^2 + 5382)/w
216w = 2w^2 + 5382
2w^2 -216w + 5382 = 0
2 (w^2 -108w + 2691) = 0
w^2 -108w + 2691 = 0
For this you really have to "plug and play" unless you have a graphing calculator. For instance, you need the sum of width (w) and length (l) to be 108. Also the product of w×l needs to be 2691. And I can only assume due to complexity that your teacher wants while numbers of feet for w and l.
So with your calculator start with a number less that 50, and divide 2691 by that. Why?? Because 50×50 = 2500 (close to 2691), and we want two different numbers because a rectangle has different widths than lengths.
So I jumped to 45, not a whole # answer, then 44, nope. 43, nope. 42, no. 41, no. 40, no. 39... yes!! 2691÷39 gives you 69, a whole #!
Now the real test: does 39+69 = 108... yes! We've got our length and width (but kinda cheated lol)! ;)
39ft × 69ft
Answer:
37 4/5 miles per hour
Step-by-step explanation:
Take the miles and divide by the time
25 1/5 ÷ 2/3
Change the mixed number to an improper fraction
(5*25 +1)/5 ÷ 2/3
126/5 ÷ 2/3
Copy dot flip
126/5 *3/2
378/10
Changing to mixed number
10 goes into 378 37 times with 8 left over
37 8/10 which simplifies to 37 4/5
37 4/5 miles per hour
Answer:
P(B and V)=10%
Step-by-step explanation:To solve this poroblema we use the formula of combinations:
C(n,r)=(nr)=n!(r!(n−r)!)
Where n is the number of objects that can be chosen and you choose r from them.
There are 5 colors of shirts.
The number of shirts that can be made by combining 2 of the 5 possible colors is calculated as:
5C2= ![\frac{5!}{2!(5-2)!}](https://tex.z-dn.net/?f=%5Cfrac%7B5%21%7D%7B2%21%285-2%29%21%7D)
5C2=10
The number of shirts that can be made by combining 2 of the 2 possible colors (B) and (V) is calculated as:
2C2=1
Then the probability is:
P( B and V)= ![\frac{1}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D)
=0.1= 10%
![\frac{2C2}{5C2}](https://tex.z-dn.net/?f=%5Cfrac%7B2C2%7D%7B5C2%7D)
Answer: 48 minutes
I just took the test and got it right.