3 years ago

Complete the Square and write in Vertex Form: f(x) = x^2 + 6x + 5

Mathematics

1 answer:

marshall27 [118]3 years ago

5 0

Answer:

no cap -check ur test thingy i got the answer from yahoo asks its x^2+6x+5

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

Solve for x 4^x=2^x+3

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Answer:

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Step-by-step explanation:

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3 years ago

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Given the function

jeka94

Answer:

<h2>The domain is all real numbers except</h2><h2>x = 3 and x = 7.</h2>

Step-by-step explanation:

We know that in a fraction the denominator must be different from 0.

Therefore:

$f(x)=\dfrac{4x+17}{x^2-10x+21}\to\ D:x^2-10x+21\neq0\\\\x^2-7x-3x+21\neq0\\\\x(x-7)-3(x-7)\neq0\\\\(x-7)(x-3)\neq0\iff x-7\neq0\ \wedge\ x-3\neq0\\\\x-7\neq0\qquad\text{add 7 to both sides}\\x\neq7\\\\x-3\neq0\qquad\text{add 3 to both sides}\\x\neq3$

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3 years ago

Y=3x write in form of ax+b

rosijanka [135]

Y=3X+0

It is already in the y= mx+b form.

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3 years ago

Complete the Square and write in Vertex Form: f(x) = x^2 + 6x + 5​

Complete the Square and write in Vertex Form: f(x) = x^2 + 6x + 5