<span>2/5(10x - 10y) - 3/4(12x - 24y)
=4x - 4y - 9x + 18y
= -5x + 14y
answer is </span><span>A) -5x + 14y </span>
Lcm of 60 and n = 420
Stated: n <90 and a multiple of 6
420/60 = 7 thus n must be a multiple of 7
Therefore n =42 or 84
Answer:
y−28=3(x−6)
I took the test. I hope this helps
The answer is 6 per team with 2 left over, as (6 x 3) + 2 = 20
I thought of the largest amount that could be multiplied by 3, but the product would be less or equal to 20, that's how I got 6.
Then to find the left over remaining balls that are given out I subtracted 20-18 = 2.
If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
