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svetlana [45]
2 years ago
6

Help ASAP Thanks :D.....

Mathematics
1 answer:
Lerok [7]2 years ago
5 0

Answer:

You are a kind smart funny person. have a good day or good night

Step-by-step explanation:

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ALGEBRA I /// Relations and Functions help!!! pls
Volgvan
Place the x values (if there are two of the same x value you only include it once) in the first box vertically like:
5
-3
6
2
Place the y values (if there are two of the same y values only include it once) in the 2nd box vertically like:
1.2
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Now draw lines from your x values to their corresponding y values.
A function may NOT have two y-values assigned to the same x-value, but it may have two x-values assigned to the same y-value.
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5 0
3 years ago
David sold a bicycle at a profit of 10% had he sold it for rupees 150 more, the profit would have been 15%. find the cost price
dlinn [17]

Answer:

The cost price was 3,000 rupees.

Step-by-step explanation:

A profit is an excess of the cost price you bought the bicycle at.

The original cost price as a decimal = 1.0

10% profit in excess of original cost as a decimal = 1+ 0.10 = 1.10

15% profit in excess of original cost as a decimal = 1+0.15= 1.15

And if he  sold the bicycle at 150rupees more,  he makes 15% profit;

The differential percentage = 15%-10% = 5% or 0.05

If 5% = 150 rupees

then 100% = (100*150)/5

= 15,000/5

= 3,000 rupees

<u>To verify;</u>

<em>At 15% profit it would be = 3000*1.15 =3,450 rupees</em>

<em>At 10% profit , it would be = 3000* 1.10 = 3,300 rupees</em>

<em>Difference = 3,450 -3,300 = 150 rupees</em>

Therefore, the cost price was 3,000 rupees.

3 0
3 years ago
Write the equation using polar coordinates y^2=16x
baherus [9]
<span>r²sin²θ = 16rcosθ </span>

<span>rsin²θ = 16cosθ </span>

<span>r = 16cosθ / sin²θ </span>

<span>r = 16cotθcscθ</span>
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3 years ago
Which solid has the top, the side, the front views given?
alexandr402 [8]

Answer:

The answer is H

Step-by-step explanation:

7 0
2 years ago
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Usimov [2.4K]
12 cubes of 1/4
Simply do 3 ><4=12 so 12 1/r cubes
4 0
3 years ago
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