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polet [3.4K]
3 years ago
8

A study of five hundred adults found that the number of hours they spend on social networking sites each week is normally distri

buted with a mean of 14 hours. The population standard deviation is 3 hours. What is the margin of error for a 95% confidence interval?
Mathematics
1 answer:
Nata [24]3 years ago
6 0
Margin of error formula:
ME = z * (Sigma) / √ n
z = 1.96 for a 95 % confidence interval;
Sigma = 3 ( the population standard deviation )
n = 500
ME = 1.96 * 3 / √500 =
= 1.96 * 3 / 22.36 =
= 5.88 / 22.36 = 0.263
Answer:
The margin error for a 95% confidence interval is 0.263.
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36 cubic inches.

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Since half is represented by \dfrac12 .

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in the following ordinary annuity interest is compounded with each payment and the payment is made at the end of the compounding
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Answer: $59313.58

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Given : Annuity payment deposit :A= $4500

rate of interest :r= 6%=0.06

No. of periods : m= 1   [∵ its annual]

Time : t= 10 years

Now we get,

FV=(4500)(\frac{(1+\frac{0.06}{1})^{1\times10})-1}{\frac{0.06}{1}})\\\\\Rightarrow\ FV=(4500)(\frac{(1.06)^{10})-1}{0.06})\\\\\Rightarrow\ FV=(4500)(\frac{0.79084769654}{0.06})\\\\\Rightarrow\ FV=(4500)(13.1807949423)\\\\\Rightarrow\ FV=59313.5772407\approx59313.58 \ \

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