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masha68 [24]
3 years ago
5

Find the midpoint of the segment with the following endpoints. (10, 7) and (5, 4)

Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:

\frac{15}{2} , \frac{11}{2}

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

\frac{x1 +x2}{2} , \frac{y1 + y2}{2}

x1 = 10

x2 = 5

y1 = 7

y2 = 4

Substituting the values in the equation, we get:-

\frac{10+5}{2} , \frac{7+4}{2}

Coordinates of the midpoint---> \frac{15}{2} , \frac{11}{2}

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If 24 ounces of apple sauce cost $2.00how much is 35 ounces
dsp73
Hint: Is under 3 dollars.
7 0
3 years ago
Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)
igor_vitrenko [27]

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x:             y:

8              -1

-------------------

-4             17

the x coor. 8  goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

4 0
2 years ago
Please help I can’t do this
worty [1.4K]
Answer to a1=6.8
a2= 0.5
mean is 6.78
i don’t know the rest sorry
4 0
2 years ago
What is 2 4/7 of 10 1/9
Fudgin [204]

Answer:

26

is the answer to the question

4 0
3 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
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