Let the smallest angle = x
Then the larger one = 71x
Supplementary angles are always equal to 180o
x + 71x = 180o Add the left side
72x = 180 Divide by 72
x = 180/72
x = 2.5
The smallest angle = 2.5 degrees
The largest angle = 2.5 * 71
The largest angle= 177.5 degrees.
So hmm the first term is -2
and if we divide one term by the term before it, we'd get the "common ratio" "r"
so hmm say -32/8 that gives us -4, so r = -4
thus
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Your answer is alredy in order
Y=7............................................................................................................................................................