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S_A_V [24]
2 years ago
11

Evaluate the question

Mathematics
1 answer:
Vesna [10]2 years ago
7 0

Answer:

we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

Step-by-step explanation:

Given the expression

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}\:=\:x^{a-b}

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=\left(\frac{2}{54}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

         =\frac{1}{\left(\frac{2}{54}\right)^{\frac{4}{3}}}

        =\left(\frac{1}{27}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}

        =\frac{1}{\frac{1^{\frac{4}{3}}}{27^{\frac{4}{3}}}}

         =\frac{1}{\frac{1^{\frac{4}{3}}}{81}}      ∵ 27^{\frac{4}{3}}=81

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{1}{\frac{b}{c}}=\frac{c}{b}

         =\frac{81}{1^{\frac{1}{3}}}              

\mathrm{Apply\:rule}\:1^a=1

         =\frac{81}{1}

          =81

Therefore, we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

                         

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