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Lady_Fox [76]
3 years ago
10

Plzzz help I will give you 25 points

Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0
Pretty sure the answer is 77
Marizza181 [45]3 years ago
3 0
answer is 77

8(9) + 5
72 + 5
77
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A taxicab charges $1.85 for the first quarter-mile and then $0.25 for every quarter mile after the first. The cost for a 17.5 mi
Roman55 [17]

Answer:

$19.10

Step-by-step explanation:

So since he charges $1.85 for the first quarter mile we can keep that as it is for now. If we add 0.25 4 times to make it $1 that would be a mile. We just have to add $17.25 plus the original $1.85 fee

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3 years ago
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(b) factorise <br>(3m-1)(6-a)-(m+3)(6-a)​
Step2247 [10]

Answer:

Step-by-step explanation:

(3m-1)(6-a)-(m+3)(6-a)

=3m(6-a)-1(6-a)-m(6-a)+3(6-a)

=18m-3ma-6+a-6m+ma+18-3a

=12m-2ma+12-2a

=2(6m-ma+6-a)

7 0
3 years ago
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
-Dominant- [34]

Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

5 0
3 years ago
Is anyone else taking Algebra 2 honors on Edge nuity? let me know!!!!
Dmitriy789 [7]

Answer:

Nope

Step-by-step explanation:

I'm in 7th grade.

6 0
3 years ago
I’ll give brainliest to the right answer plz help
BigorU [14]

9514 1404 393

Answer:

  water

Step-by-step explanation:

Comparison of numbers can be done a couple of different ways. One way is to subtract one from the other. If the difference is positive, the minuend (first number) is the larger of the two.

Another way is to divide one number by the other. If the ratio is more than 1, then the numerator is the larger number.

For numbers in scientific notation, the division is perhaps the easiest. Here, that gives you ...

  \displaystyle\frac{\text{water mass}}{\text{oxygen mass}}=\frac{2.99\times10^{-26}\text{ kg}}{2.66\times10^{-26}\text{ kg}}=\frac{2.99}{2.66}\approx 1.12

This value is greater than 1, so the mass of a water molecule is greater.

__

You will note that the multipliers (10^-26 kg) cancelled because they were equal. If they are unequal, the usual rules of exponents apply.

5 0
3 years ago
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