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3 years ago

9

pls pls pls, I beg you to answer this question only if you know the correct answer please please please I beg you please I beg y

ou no n no no no link

1 answer:

Sonbull [250]3 years ago

4 0

Answer:

I THINK its -2 -3

Step-by-step explanation:

-2 -3

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Solve for x.<br> 21x + 11 - 5 = 5

Reil [10]

Answer:

x= -1/21

Step-by-step explanation:

21x + 11 - 5 = 5

21x + 6 = 5

(-6 each side)

21x = -1

(divide 21 each side)

x= -1/21

3 0

3 years ago

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Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago

SUSAN AND TEO PLAY SOCCER. SUSANS TEAM PLAYS EVERY FIVE DAYS. TEO'S TEAM PLAYS EVERY SIX DAYS. WHEN WILL THE TWO TEAMS PLAY TOGE

salantis [7]

Yes the answer is 30.

3 0

3 years ago

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A solid aluminum cube has sides each of length l . A second cube of the same material has sides four times the length of the fir

timofeeve [1]

The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3

3 0

4 years ago

Today, the price of a new cell phone is $129.

Gnom [1K]

Answer:

54%

Step-by-step explanation:

129/240 = 0.5375 (divided to find the % change)

0.5375 * 100 (to convert decimal to percent form)

53.7 which is rounded to 54 percent (I needed to round it to the nearest whole percent number)

8 0

3 years ago

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