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My name is Ann [436]
3 years ago
11

I really need help with this FAST PLEASE!!!!!

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0
It is 1 and - 3 so b yeah
jenyasd209 [6]3 years ago
8 0
(-3,0) and (1,0) are x-intercepts
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If m∠A = 56°, m∠B = 60°, and c = 8, what is the measure of side length b?
Alekssandra [29.7K]

Using the law of sines:

\frac{b}{sin(B)}=\frac{c}{sin(C)}

Solve for b:

\begin{gathered} b=\frac{c\cdot sin(B)}{sin(C)} \\ so: \\ b=\frac{8\cdot sin(60)}{sin(64)} \\ b\approx7.708 \end{gathered}

Answer:

7.708

5 0
1 year ago
Help me out on this one i will give u brainlyiest
nexus9112 [7]

Answer:

<h2>12 4/8</h2>

Step-by-step explanation:

1. First step

ADD

7+4=11

7+5=12

so

11\frac{12}{8}

2. Second step

Now simplify

11 12/8 = 12 4/8 = 12 1/2

----------------------------------------------------------------------------------------------------------

Thanks!

Answered by: FieryAnswererGT

#learnwithbrainly

Want to thank me? JUST MARK ME BRAINLIEST! So simple!

5 0
2 years ago
Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too?
rusak2 [61]

<em>Question 5</em>

Vertical angles are <u>congruent</u>. Therefore, 3y=\boxed{150}. The sum of two supplementary angles equals \boxed{180^{\circ}}.

Therefore, 6x+150=\boxed{180}

<em>Question 6</em>

\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}

<em>Question 7</em>

<em />\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}

<em>Question 8</em>

<em />7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}

6 0
2 years ago
X°<br> 1<br> 63°<br> m<br> n<br> find the value of x
Aleonysh [2.5K]

Answer:

I believe its 63°......,.,..,.,.,.,

8 0
3 years ago
a quadrilateral has vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4). Quadrilateral ABCD is a . If the vertix C(11,-1) were shi
Maurinko [17]

Answer:

A quadrilateral formed by the vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4) forms a rhombus

If the vertex C(11,-1) were shifted to the point C'(11,1), quadrilateral ABC'D would be a kite

Step-by-step explanation:

A quadrilateral formed by the vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4) forms a rhombus. A rhombus is a quadrilateral whose all sides have equal length means it has four equal sides.

If the vertex C(11,-1) were shifted to the point C'(11,1), quadrilateral ABC'D would be a kite because a kite has two pairs of equal sides. A kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides which are adjacent to each other....

7 0
3 years ago
Read 2 more answers
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