Probability that the first card is not a club is 1 minus probability that it is a club. i.e. 1 - 1/4 = 3/4
Probability that the second card is a diamond = 1/4
Probability that the first card is not a club AND the second card is a diamond is 3/4 x 1/4 = 3/16
Answer:
x=4
Step-by-step explanation: So you do 2x plus 1x which is 3x. Then you divide both sides by 3 which leaves you with x=4. Thats your answer. <3
Answer:
(a)
and
are indeed mutually-exclusive.
(b)
, whereas
.
(c)
.
(d)
, whereas 
Step-by-step explanation:
<h3>(a)</h3>
means that it is impossible for events
and
to happen at the same time. Therefore, event
and
are mutually-exclusive.
<h3>(b)</h3>
By the definition of conditional probability:
.
Rearrange to obtain:
.
Similarly:
.
<h3>(c)</h3>
Note that:
.
In other words,
and
are collectively-exhaustive. Since
and
are collectively-exhaustive and mutually-exclusive at the same time:
.
<h3>(d)</h3>
By Bayes' Theorem:
.
Similarly:
.
Idk i literally get one away for everything i do
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