3 years ago

I really need help with this

Mathematics

1 answer:

IceJOKER [234]3 years ago

3 0

The correct answer is D!

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Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.33$

Now, find the margin of error M as such

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In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$\sigma = 5, n = 100$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.33*\frac{5}{\sqrt{100}} = 1.165$

So the correct answer is:

1.165.

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3 years ago

The accompanying stem-and-leaf plot represents Kiko's test scores this year. What is the median score for this set of data?

worty [1.4K]

Answer: 80

Write down all the values and cross out until you get to the middle, since there are 2 values, find the mean, which would be 80

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