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lakkis [162]
3 years ago
13

( LETS SEE IF YOUR SMART )

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Answer:

6\leq x\leq 12

Step-by-step explanation:

First we have to write down what it says in the question in as an expression. So we know that there is already 3 people on Britany's team (herself and the two friends),  that in order to participate in the league you will need at least 9 players, and that the team can have a maximum of 15 player. So....

Let "x" be the number of people who decided to join Britany and her friends

Let "y" be the total number of people on Britanie's team, then .....

3 + x = y

Now we need to remember that in order to participate in the league you will need at least 9 players, and that the team can have a maximum of 15 player. We can write that down as......

9\leq y\leq 15

Now from this we know that the minimum value that x would need to take in order for Brittany's team to participate can be found by solving 3 + x = 9. The maximum value that x would need to take in order for Brittany's team to participate can be found by solving 3 + x = 15. And so we get.....

Minimum value:

3 + x = 9

x = 9 -3

x = 6

Maximum value:

3 + x = 15

x = 15 - 3

x = 12

Now we know that x will be equal to any integer between 6 and 12 so

6\leq x\leq 12

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3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

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8 0
2 years ago
Write the quadratic equation whose roots are -2 and 1, and whose leading coefficient is 4 .
Kaylis [27]

Answer: the equation is

4x^2 + 4x - 12

Step-by-step explanation:

A quadratic equation is an equation in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where

a is the leading coefficient

c is a constant

Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.

Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)

the equation becomes

(x+2)(x-1)

= x^2 - x +2x - 3

= x^2 + x - 3

Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes

4(x^2 + x - 3)

= 4x^2 + 4x - 12

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