L = hours used by the Lopez's sprinkler
R = hours used by the Russell's sprinkler
so, we know the Lopez's sprinkler uses 15 Liters per hour, so say after 1 hour it has used 15(1), after 2 hours it has used 15(2), after 3 hours it has used 15(3) liters and after L hours it has used then 15(L) or
15L.
likewise, the Russell's sprinkler, after R hours it has used
40R, since it uses 40 Liters per hour.
we know that both sprinklers combined went on and on for 45 hours, therefore whatever L and R are,
L + R = 45.
we also know that the output on those 45 hours was 1050 Liters, therefore, we know that
15L + 40R = 1050.

how long was the Lopez's on for? well, L = 45 - R.
-3+8.
We know that the temperature /was/ -3, so it was 3 under zero. It has /risen/ by 8, meaning we have added 8 degrees to whatever the starting temperature was.
We can find out how much the temperature is right now: it was -3, went through -2, -1, 0, 1, 2, 3, 4, and now its at 5 degrees. Thats risen by 8 degrees, right? And -3+8 is the same as 8-3 (commutative property of addition, since we basically did 8+(-3)) which equals 5, so we know that we got the correct answer. :)
Answer:
Height of cone (h) = 14.8 in (Approx)
Step-by-step explanation:
Given:
Radius of cone (r) = 6 in
Slant height (l) = 16 in
Find:
Height of cone (h) = ?
Computation:
Height of cone (h) = √ l² - r²
Height of cone (h) = √ 16² - 6²
Height of cone (h) = √ 256 - 36
Height of cone (h) = √220
Height of cone (h) = 14.832
Height of cone (h) = 14.8 in (Approx)
Answer: The distance around the lot is given by

Step-by-step explanation:
Since we have given that
Length of rectangular lot is given by

Width of rectangular lot is given by

We need to find the distance around the lot.
As we know the formula for "Perimeter of rectangle":

Hence, the distance around the lot is given by

Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5