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Tamiku [17]
2 years ago
7

PLEASE HELP will Brainlist 30 points!!!!!!!!

Mathematics
2 answers:
Effectus [21]2 years ago
8 0
It is the first one
DIA [1.3K]2 years ago
3 0

Answer:

A. JLK

Step-by-step explanation:

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A math class has three girls and 7 boys in the 7th grade and five girls and five boys in the 8th grade the teacher randomly sele
Anuta_ua [19.1K]

Answer:

7/20

Step-by-step explanation:

Seventh grade: Total = 3 + 7 = 10

Number of boys = 7 boys

Probability of a boy being picked = 7/10

Eighth grade: Total 5 + 5 = 10

Number of boys = 5

Probability 5/10 = 1/2

The probability of the correct outcome = 7/10  *  1/2  = 7 / 20

Answer: 7 / 20

7 0
3 years ago
Find the value of x in the triangle shown below.
ycow [4]

Answer:

30 Degrees for sure

6 0
3 years ago
3) Divide x3 + 4x2 – 3x – 12 by (x + 4)
alex41 [277]

Answer:

Factor the numerator and denominator and cancel out the common factors.

x ^2 − 3 is your final answer.

Step-by-step explanation:

Hope that this helps you out! :)  

If you have any questions please put them in the comment section below this answer.  

Have a great rest of your day/night!  

Please thank me on my profile if this answer has helped you.

7 0
2 years ago
Divide 254 by 11.8. Round your answer to the nearest hundredth. A. 20.97 B. 21.53 C. 21.35 D. 22.07
Rainbow [258]
The answer is B 21.53
7 0
3 years ago
Read 2 more answers
Suppose that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage
Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29​%.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage of blue candies is equal to 29​%.

Let p = <u><em>population percentage of blue candies</em></u>

So, Null Hypothesis, H_0 : p = 29%     {means that the percentage of blue candies is equal to 29​%}

Alternate Hypothesis, H_A : p \neq 29%     {means that the percentage of blue candies is different from 29​%}

The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;

                         T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of blue coloured candies = 28%

           n = sample of colored​ candies = 100

So, <u><em>the test statistics</em></u> =  \frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }

                                    =  -0.22

The value of the z-test statistics is -0.22.

<u>Also, the P-value of the test statistics is given by;</u>

               P-value = P(Z < -0.22) = 1 - P(Z \leq 0.22)

                            = 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29​%.

4 0
3 years ago
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