<span>45 x (1.08) x </span>30 = 1458
-----------------------------------------------
Answer:
187.95 liters.
Step-by-step explanation:
the entire capacity of the tank is 200 liter, you subtract how much oil is in there already, you will have the remaining Of the capacity that can be added.
200 - 12.05 = 187.95
Answer:



Step-by-step explanation:
Given
See attachment for triangle
Required
Find
and
of angle Y
For angle Y:


The
of an angle is calculated as:

So:

The
of an angle is calculated as:

So:

The
of an angle is calculated as:

So:

Answer:


Step-by-step explanation:
Given

Solving (a): Write as inverse function

Represent a(d) as y

Swap positions of d and y

Make y the subject


Replace y with a'(d)

Prove that a(d) and a'(d) are inverse functions
and 
To do this, we prove that:

Solving for 

Substitute
for d in 




Solving for: 

Substitute 5d - 3 for d in 

Add fractions



Hence:

Answer:
A.
General Formulas and Concepts:
<u>Math</u>
- Fraction conversions to decimal
<u>Algebra I</u>
- Reading a Cartesian plane
- Coordinates (x, y)
Step-by-step explanation:
Where the 2 lines intersect is the solution to the systems of equations.
5/2 would be 2.5 and 4/3 would be approximately 1.333.
Our (x, y) for the graph is (2.405, 1.357), so our answer would be A.