Answer:
y=(x+3)^2 has a vertex at (-3,0), while y=x^2 + 3 has a vertex at (0,3)
Mark me brainliest hope this helps
Step-by-step explanation:
x<5
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x = 4 and -10
Given the equation
x²+6x-40= 0
The common factors to use for the factorisation are +10 and -4
x²+(10x-4x)-40=0
(x²+10x)-(4x-40) = 0
x(x+10)-4(x+10) = 0
(x-4)(x+10) = 0
x-4 =0 and x+10 = 0
x = 4 and x = -10
x = -1
-1 + 3 = 2
-(-1) + 1 = 2 or 1 + 1 = 2
