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Ilya [14]
3 years ago
7

Annie was told that her math test score was 3 standard deviations below the mean. If test scores were approximately normal with

μ=99 and σ=4, what was Annie's score? Do not include units in your answer. For example, if you found that the score was 99 points, you would enter 99.
Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Answer:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

Step-by-step explanation:

Let X the random variable that represent the test scores of a population, and for this case we know the distribution for X is given by:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

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3 years ago
1-Suppose the path of a baseball follows the path graphed by the quadratic function ƒ(d) = –0.6d2 + 5.4d + 0.8 where d is the ho
jasenka [17]

Answer:

1. The correct option B.

2.The correct option A.

Step-by-step explanation:

The given function is

f(d)=-0.6d^2+5.4d+0.8

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

0=-0.6d^2+5.4d+0.8

Quadratic formula:

d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using the quadratic formula we get

d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}

d=-0.146,9.146

Therefore the ball is in air between d=-0.146 to d=9.146.

The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

9.146\approx 9.15

Therefore the correct option is B.

2.

The given equation is

y=(x-1)^2+1                 .... (1)

The standard form of parabola is

y=a(x-h)^2+h             .... (2)

Where, a is constant and (h,k) is vertex.

On comparing (1) and (2), we get

a=1

h=1

k=1

Since the value of a is positive, therefore it is an upward parabola. The vertex of the parabola is (1,1).

Put x=0 in the given equation.

y=(0-1)^2+1

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Therefore the y-intercept is (0,2) and option A is correct.

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Answer:

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Step-by-step explanation:

Use your fingers if necessary

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Answer:

A & C & D

Step-by-step explanation:

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