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Ilya [14]
3 years ago
7

Annie was told that her math test score was 3 standard deviations below the mean. If test scores were approximately normal with

μ=99 and σ=4, what was Annie's score? Do not include units in your answer. For example, if you found that the score was 99 points, you would enter 99.
Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Answer:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

Step-by-step explanation:

Let X the random variable that represent the test scores of a population, and for this case we know the distribution for X is given by:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

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Read 2 more answers
Graph the functions and approximate an x-value in which the exponential function exceeds the polynomial function. y = 4x y = 7x2
nordsb [41]

Answer:

The Exponential function is

y=4^x

And the polynomial function is

y=7 x^2 +4 x -2

And, we have to find the value of x for which, exponential function exceeds the polynomial function which can be written as

4^x> 7 x^2 +4 x -2

1. When , x= -1

LHS

4^{-1}=\frac{1}{4}=0.25

RHS

=7*(-1)^2 +4 *(-1)-2\\\\=7-4-2=1

2. When , x=0

L HS

 4^0=1

RHS

7*0+4*0-2= -2

3. When ,x= 0.5

L HS

 4^{0.5}=2

RHS

=7*0.25 +4*0.5 -2\\\\= 1.75+2-2\\\\=1.75

4. When , x=2

LHS

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RHS

=7*4^2+4*4-2\\\\=112+16-2\\\\=126

The Minimum value for which  exponential function exceeds the polynomial function is , x= 0.5

But,there is other value for which  exponential function exceeds the polynomial function is , x=2.

5 0
3 years ago
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