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Ilya [14]
3 years ago
7

Annie was told that her math test score was 3 standard deviations below the mean. If test scores were approximately normal with

μ=99 and σ=4, what was Annie's score? Do not include units in your answer. For example, if you found that the score was 99 points, you would enter 99.
Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Answer:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

Step-by-step explanation:

Let X the random variable that represent the test scores of a population, and for this case we know the distribution for X is given by:

X \sim N(99,4)  

Where \mu=99 and \sigma=4

We want to find the Annie's score takign in count that the score is 3 deviations below the mean, so then we can find the value with this formula:

X = \mu -3\sigma

And replacing we got:

X = 99 -3*4 = 87

So then the Annie's score would be 87

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Answer:

The average rate of change of the function over the interval is of 6.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function h(x) over an interval [a,b] is given by:

A = \frac{h(b)-h(a)}{b-a}

In this question:

Over the interval [-9,-2], so a = -9, b = -2, b - a = -2 -(-9) = 7

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h(-9) = -9^2 -5(-9) + 14 = -81 + 45 + 14 = -22

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Then

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The average rate of change of the function over the interval is of 6.

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