All categories

3 years ago

Please helpppppppppp

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

$kb = {2}^{10} \\ gb = {2}^{30}$

tb = product of kb and gb

$tb = kb \times gb \\ tb = {2}^{10} \times {2}^{30} \\ = {2}^{40}$

You might be interested in

51/68 in simplest form

yanalaym [24]

Answer:3/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Pleassssssseeeeeee heeelllllppppppppp

olga2289 [7]

Answer: 1. point A

2. 90 degrees

3. 90 degrees clockwise

Step-by-step explanation:

BRAINLIEST??!?!

6 0

3 years ago

HELPPPPPP PLEASE! URGENT

Effectus [21]

Answer:

x=59 y= 81 z= 99

Step-by-step explanation:

180-(57+24)=99

y=180-99=81

x= 40+81=121

180-121=59

3 0

2 years ago

Plant B is 6 2/3 inches tall. and C is 4 4/15 inches tall. Complete the sentences and show your reasoning

artcher [175]

Answer:

Plant C is <u>0.64</u> times as tall as Plant B

Plant C is <u>2.4 inches</u> shorter than Plant B

Step-by-step explanation:

Plant B is 6 2/3 inches tall. Plant B is 20/3 inches tall.

Plant C 4 4/15 inches tall. Plant C is 64/15 inches tall.

a.) Plant C is shorter than Plant B $= \frac{64}{15} \times \frac{1}{\frac{20}{3} } = \frac{64}{15} \times\frac{3}{20} = \frac{16}{25}$ = 0.64 times.

b.) Plant C is shorter than Plant B by = $\frac{20}{3} - \frac{64}{15} = \frac{100}{15} - \frac{64}{15} = \frac{100 -64}{15} = \frac{36}{15} = 2\frac{2}{5} = 2.4$ inches

3 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n

Ratling [72]

Answer:

$k = \dfrac{1}{21}$

b) 0.476

c) 0.667

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

$P(y) = ky$

a) Property of discrete probability distribution:

$\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}$

b) at most four forms are required

$P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476$

c) probability that between two and five forms (inclusive) are required

$P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667$

8 0

3 years ago