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leonid [27]
3 years ago
10

Solve this question NO SPAM​

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

hope this helps you

God bless you ☺️☺️

IrinaVladis [17]3 years ago
5 0

Answer:

Answer is option A and D

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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The sum of opposite angles are equal, so two of the angles are 45°.  The sum of all angles about the intersection of two lines is 360°.  So the remaining two angles are found by:

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Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

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but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

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