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Leni [432]
3 years ago
7

141.75 rounded to the nearest hundredth

Mathematics
1 answer:
muminat3 years ago
6 0

Answer:

141.75

Step-by-step explanation:

Since it is already rounded to the nearest hundredth, you don't need to do anything.

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Could you please check my answers and let me know if they are right?
ANTONII [103]

Answer:

11 is correct

12 should be 51°

Step-by-step explanation:

15/sin(104) = 12/sin(J)

J = 50.917°

8 0
3 years ago
Help me plsssssssss its easy and show work please
babymother [125]

Answer:

» For x-intercept, y is zero

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>3</u><u>2</u><u> </u>

{ \tt{0 =  {x}^{2} - 12x + 32 }} \\ { \tt{ {x}^{2} - 12x + 32 = 0 }} \\ { \tt{(x - 8)(x - 4) = 0}} \\ { \tt{x = 8 \:  \: and \:  \: 4}} \\  { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (8, \: 0) \:  \: and \:  \: (4, \: 0) \:  \: }}}

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u>2</u><u>4</u><u> </u><u>:</u>

{ \tt{0 =  {x}^{2}  - 10x + 24}} \\ { \tt{ {x}^{2}  - 10x + 24 = 0}} \\ { \tt{(x - 6)(x - 4) = 0}} \\ { \tt{x = 6 \:  \: and \:  \: 4}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (6, \: 0) \:  \: and \:  \: (4, \: 0) \:  \: }}}

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>6</u><u> </u><u>:</u>

{ \tt{0 =  {x}^{2}  + 10x + 16}} \\ { \tt{ {x}^{2} + 10x + 16 = 0 }} \\ { \tt{(x + 2)(x + 8) = 0}} \\ { \tt{x =  - 2 \:  \: and \:  \:  - 8}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \:  \: and \:  \: ( - 8, \: 0) \:  \: }}}

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>2</u><u>5</u><u> </u><u>:</u>

{ \tt{0 =  {x}^{2}  - 25}} \\ { \tt{ {x}^{2}  = 25}} \\ { \tt{ \sqrt{ {x}^{2}  } =  \sqrt{25}  }} \\ { \tt{x =  \pm5}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (5, \: 0) \:  \: and \:  \: ( - 5, \: 0) \:  \: }}}

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{ \tt{0 =  {x}^{2} + 8x + 12 }} \\ { \tt{ {x}^{2} + 8x + 12 = 0 }} \\{ \tt{(x + 2)(x + 6) = 0}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \:  \: and \:  \: ( - 6, \: 0) \:  \: }}}

8 0
3 years ago
Over what interval is the function differentiable? Y=3/2(x-1)
jolli1 [7]

<u>Answer-</u>

<em>The interval where the function is diffrentiable is </em>

[-\infty,1)\ \bigcup\ (1,\infty]

<u>Solution-</u>

The given expression is,

y=\dfrac{3}{2(x-1)}

The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.

The function continuous everywhere except at x = 1, because

\Rightarrow 2(x-1)=0\\\\\Rightarrow x-1=0\\\\\Rightarrow x=1

at x = 1, its limit does not exist.

Therefore, apart from x=1, this function is differentiable everywhere. The interval will be

[-\infty,1)\ \bigcup\ (1,\infty]

3 0
3 years ago
A bicycle wheel travels 267 in, for each revolution. What is the radius of the wheel?
miss Akunina [59]
So 26 π = perimeter, then
26 π = 2 π r; 13 π = π r; 13=r
5 0
3 years ago
Please help me answer number 5
malfutka [58]

Step-by-step explanation:

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6 0
3 years ago
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