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svetoff [14.1K]
3 years ago
6

Explain how SEO impacts the way you should interpret search engine results ???

Computers and Technology
1 answer:
enot [183]3 years ago
8 0

Answer:

For the majority of businesses, the goal of SEO is to gain leads from search engines, by:

  • Increasing organic traffic.
  • Increasing keyword rankings.
  • Ranking for more keywords.

You might be interested in
True / False
Tju [1.3M]

Answer:

TRUE, The PC is always incremented by the same amount in fixed-length instruction set architectures.

Explanation:

Its TRUE that Program Counter ( PC ) is always incremented by the same amount in fixed - length instruction set architectures ( fixed length ISA) . As the instruction set length is fixed in fixed - length instruction set architectures, the Program Counter to fetch the next instruction set it has to be incremented by fixed length. This fixed length depends on the hardware of the architecture (the number of bytes each machine word contains and number of machine words per memory location)

7 0
4 years ago
Write a program that will remove "May" from the list using .Pop and .Index methods.(5pts) GIVEN: lst=["January", "February", "Ma
Inga [223]

Answer:

This question is answered in Python

lst=["January", "February", "March", "April", "May", "June"]

index = lst.index('May')

lst.pop(index)

print(lst)

Explanation:

This initializes the list

lst=["January", "February", "March", "April", "May", "June"]

This gets the index of May

index = lst.index('May')

This removes "May" from the list using pop()

lst.pop(index)

This prints the updated list

print(lst)

5 0
4 years ago
A blue compressor clutch indicates that it's been slipping due to too
SVETLANKA909090 [29]

Answer:

Hi,

This effect can be due to <u>dull/ unpolished clutch c</u>aused by incorrect amount of oil in the system

Explanation:

Clutch is the third highest failures observed in AC after hose leaks and compressors.Some of the clutch related failures are bearing failure, burnt coil, unbalanced motor to air hub gap, noisy bearing ,and unpolished clutch.Burnishing of a clutch is when the wearing  of the engagement surface if the clutch is allowed to increase the starting torque.The effect of dull clutch is that it produces low staring torque making it to slip and fail.When too much oil is applied, it will cause the compressor to slug and the clutch to slip.Low amounts of oil will cause the compressor to bind and the clutch to slip because of increased discharge pressures in the system.

Best of Luck!

6 0
4 years ago
What are the six external part of a computer
pashok25 [27]
I'm guessing you mean the six external parts as in input and output devices

Here are the six external parts:

>Keyboard

>Mouse

>Monitor

>Speakers

>Printer

>Microphone or USB...I think you can choose either one as they are components outside of the computer/external/ -I/O devices
5 0
3 years ago
Read 2 more answers
HW4:
julsineya [31]

Answer:

Check the explanation

Explanation:

1)

import java.util.*;

public class ArrayStack {

// Declare an Array List

ArrayList<String> aList;

// Constructor that Instantiates arrayList object

ArrayStack() {

aList = new ArrayList<String>();

}

public void push(String object) {

//Add the Value

aList.add(object);

}

public String pop() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// Remove it

ret = aList.get(aList.size() - 1);

aList.remove(aList.size() - 1);

}

return ret;

}

public String peek() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// DO not remove it

ret = aList.get(aList.size() - 1);

}

return ret;

}

public boolean isEmpty() {

//Check the size of list if 0 means Stack is Empty

return aList.size()==0;

}

public static void insertionSort(int arr[], int n)

{

int i, j;

for(i=2;i< n;i++){

arr[0] = arr[i];

j = 1;

while(j <= i-1){

/* implement your code here /*

/* you must start compare arr[j] with a[0], notice that j = 1 */

}

}

}

public static void main(String[] args) {

// TODO Auto-generated method stub

ArrayStack aStack = new ArrayStack();

aStack.push("Hey");

aStack.push("Hello");

aStack.push("Bye");

System.out.println(aStack.pop());

System.out.println("Peek: " + aStack.peek());

System.out.println(aStack.pop());

System.out.println(aStack.isEmpty());

System.out.println(aStack.pop());

// int arr[] = new int[] {3,4,2,1,6,7,5};

// insertionSort(arr,7);

// System.out.println(Arrays.toString(arr));

}

}

LinkedQueue

interface QueueInterface {

public void enqueue(Object item);

// Effect: Adds item to the rear of this queue.

// Precondition: This queue is not full.

// Postcondition: item is at the rear of this queue.

public Object dequeue();

// Effect: Removes front element from this queue and returns it.

// Precondition: This queue is not empty.

// Postconditions: Front element has been removed from this queue.

// Return value = (the removed element)

public boolean isEmpty();

// Effect: Determines whether this queue is empty.

// Postcondition: Return value = (this queue is empty)

public boolean isFull();

// Effect: Determines whether this queue is full.

// Postcondition: Return value = (queue is full)

public int size();

}

public class LinkedQueue implements QueueInterface {

private class QueueNode

// Used to hold references to queue nodes for the linked queue

// implementation

{

private Object info;

private QueueNode link;

}

private QueueNode front; // reference to the front of this queue

private QueueNode rear; // reference to the rear of this queue

public LinkedQueue()

// Constructor

{

front = null;

rear = null;

}

public void enqueue(Object item)

// Adds item to the rear of this queue.

{

QueueNode newNode = new QueueNode();

newNode.info = item;

newNode.link = null;

if (rear == null)

front = newNode;

else

rear.link = newNode;

rear = newNode;

}

public Object dequeue()

// Removes front element from this queue and returns it.

{

Object item;

item = front.info;

front = front.link;

if (front == null)

rear = null;

return item;

}

public boolean isEmpty()

// Determines whether this queue is empty.

{

if (front == null)

return true;

else

return false;

}

public Object peek()

// Determines whether this queue is empty.

{

if (front == null)

return null;

else

return front.info;

}

public int size()

// Determines whether this queue is empty

{

QueueNode curr = front;

int count = 0;

while (curr != null) {

++count;

curr = curr.link;

}

return count;

}

public String toString()

// Determines whether this queue is empty.

{

QueueNode curr = front;

String res = "";

while (curr != null) {

res = res + curr.info + " ";

curr = curr.link;

Note that i could not complete the answers to all the question because the codes are above the brainly character limit, you might need to ask the question 2 and 3 separately.

Kindly check the outputs in the attached images below

5 0
4 years ago
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