All categories

2 years ago

Fill in the coefficient needed to make the equation balanced.

Chemistry

1 answer:

Natali [406]2 years ago

4 0

Answer:

1 a

2 b

3 a

4. c

Explanation:

You might be interested in

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

4 0

2 years ago

Scientists want to eventually collect data from the surface of Venus. Which is a technology that could be used to collect sample

ivanzaharov [21]

Answer:

Explanation:

Because im smart

6 0

3 years ago

NaOH + HCl → NaCl + H2O. What mass of water forms when 2.75 × 10–4 mol NaOH reacts completely? given the equation, 2.75 × 10–4 m

Hoochie [10]

The balanced chemical reaction is written as:

<span>NaOH + HCl → NaCl + H2O

We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation.

2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O</span>

5 0

3 years ago

Read 2 more answers

Permafrost soil (gelisol) is _______.

kvasek [131]

Permafrost soil (gelisol) is b) fragile.

7 0

3 years ago

Read 2 more answers

A sample of 5.30 mLmL of diethylether (C2H5OC2H5;density=0.7134g/mL)(C2H5OC2H5;density=0.7134g/mL) is introduced into a 6.50 L L

lilavasa [31]

Answer:

1.16atm

Explanation:

We are going to derive the mass of ether from density

mass=density *volume

Also moles=mass/molecular mass

molar mass C2H5OC2H5 =74.12 g/mole

the density of ether is 0.7134 g/ml

mass C2H5OC2H5 = 5.30 ml x 0.7134 g/ml = 3.78 g

moles C2H5OC2H5 =3.78 g x 1 mole/74.12 g = 0.0509 moles

PV = nRT where P=?; n=0.0509 moles; V=6.50L; R=0.0821 Latm/Kmol; T=35ºC +273 = 308K

P = nRT/V = 0.0509)(0.0821)(308)/6.50

P = 0.198 atm (to 3 significant figures (this is the partial pressure of diethyl ether).

TOTAL PRESSURE

P1+p2+p3

= 0.198 atm + 0.750 atm + 0.207 atm =1.1550atm

1.16atm(3 significant figures)

5 0

3 years ago