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sladkih [1.3K]
3 years ago
12

NEED HELP!!! pls help mee :)

Chemistry
1 answer:
iogann1982 [59]3 years ago
6 0
1) favor reverse
2) favor reverse
3) favor forward
4) favor forward
5) favor reverse

I believe these are right
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Please answer the question
Tom [10]

Answer:

Stamens

Explanation:

7 0
3 years ago
The conjugate acid of a particular halide has a pka = 3. a student wants to use this halide in a substitution reaction thinking
Taya2010 [7]

Since the leaving ability of the halide ions increasees as the basicity of the halide decreases.

If the basicity of the halide decreases as the its conjugate acid is strong.

Since the pKa value of conjuage acid of haldie is 3, it is a weak acid. So, it halide is not a good leaving group.

Therefore the answer is No, because a good leaving group is the conjugate base of a strong acid. The halide not acidic enough to be a good leaving group.

5 0
3 years ago
Explain how the atom is electrically neutral, having an equal number of protons and electrons.
lord [1]

Answer:

A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other and atom become neutral.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other and atom become neutral. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example

The carbon have six protons and six neutrons so its atomic mass is 12 amu and atomic number is six.

5 0
3 years ago
In a second-order reaction (one that is second order in one reactant), cutting in half the concentration of that reactant will h
Keith_Richards [23]
rate 1 of the reaction = k [A]²

rate 2 of the reaction = k [A/2]² = k[A]² /4

We can see that rate of the reaction will be 4 times less.
8 0
4 years ago
If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg(OH)2, what is the concentration of the Mg(OH) 2 soluti
xenn [34]
2 HBr + Mg(OH) 2 yields Mg(Br) 2 + 2 H2O
M1V1 = M2V2
(0.245 M)(37.5 mL) = (M2)(18.0 mL)
9.1875 = (M2)(18.0 mL)
9.1875/(18.0 mL) = (M2)(18.0 mL)/(18.0 mL)
0.51041
this is not the complete answer as the mol to mol ratio must be considered!
For every 2 mols of HBr there is 1 mole of <span>Mg(OH)2; ratio = 2:1
</span>0.51041 / 2 = 0.25520
M2 = 0.25520
0.25520 M of<span> Mg(OH)2 solution</span>
7 0
4 years ago
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