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mars1129 [50]
3 years ago
12

Gasoline has a density of 0.749 g/mL. How many pounds does 19.2 gallons of gasoline weigh? Use significant figures. Do not enter

“pounds” as part of your answer.
Chemistry
1 answer:
Yanka [14]3 years ago
7 0
In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:

mass of gasoline= density * volume
mass of gasoline=  0.749g/ml * (1 pound/453.592grams) * 3785.41ml/gallon * 19.2 gallon= 120 pounds

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When sulfate (SO42-) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is?
o-na [289]

When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).

How sulfate acts as electon acceptor and electron donor?

  • Sulfate (SO₄²⁻) is used as the electron acceptor in sulfate reduction, which results in the production of hydrogen sulfide (H2S) as a metabolic byproduct.
  • Many Gram negative bacteria identified in the -Proteobacteria use sulfate reduction, which is a rather energy-poor process.
  • Gram-positive organisms connected to Desulfotomaculum or the archaeon Archaeoglobus also utilise it.
  • Electron donors are needed for sulfate reduction, such as hydrogen gas or the carbon molecules lactate and pyruvate (organotrophic reducers) (lithotrophic reducers).

Learn more about the Electron transport chain with the help of the given link:

brainly.com/question/24372542

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3 0
1 year ago
The weight on an object depends on its(blank)and the(blank) of Earth.
Nonamiya [84]

Answer:

mass and height? idfk

Explanation:

ik mass is correct tho

7 0
3 years ago
Mr. Bullis wants to know if he gives teachers candy, it will make them smile more. He gives half the teachers candy and the othe
mote1985 [20]

Answer:

the experimental group would be the teachers who recieved the candy

control group would be the teachers who dont get any candy

<em>Explanation:</em>

experimental group is the group that receives the test variable being tested in this case the variable being the candy

and the control group is the group who doesn't receive the variable

purpose of having a control is to rule out other factors which may influence the results of an experiment.

5 0
2 years ago
Can anyone answer the riddle of the day; Is water wet?
Afina-wow [57]
No, if something is wet then it has water on it that can be removed, you cannot take water off of itself.
3 0
3 years ago
Read 2 more answers
Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)
allsm [11]

Answer:

\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}

Explanation:

1. Density from mass and volume

\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}

2. Volume from density and mass

V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}

3. Mass from density and volume

\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}

4. Density by displacement

Volume of water + object = 24.6 mL

Volume of water                =<u> 12.8 mL</u>

Volume of object               = 11.8 mL

\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

 

6 0
3 years ago
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