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fredd [130]
2 years ago
6

What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4,

Mathematics
1 answer:
choli [55]2 years ago
4 0

Answer: \frac{1}{3}

Step-by-step explanation:

total sides = 6

p (rolling a 1) = \frac{1}{6}

p (rolling a 2) = \frac{1}{6\\}

Note:

or - add

and - multiply

∴ \frac{1}{6} +\frac{1}{6} = \frac{2}{6}

∴ \frac{2}{6} = \frac{1}{3}

hence, p (rolling a 1 or 2) = \frac{1}{3}

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I will give brainliest to one of the correct answers.
statuscvo [17]

Answer:

1. 7/41

2. 7/15

Step-by-step explanation:

1. Probability that it is a multiple of 6 given that it is a 2 digit number: There are 7 numbers that are a multiple of 6 and are 2 digits: 12, 18, 24, 30, 36, 42, and 48. There are 41 numbers that are 2 digits. So, it is 7/41

2. Probability that it is at least 20 given that it is prime. Out of the prime numbers from 1-50, 7 of them are at least 20 and there are 15 primes in that range in total. So, it is 7/15

3 0
3 years ago
The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

6 0
3 years ago
Sarah received $55 for her birthday. She used some of that money to buy 3 shirts priced at m dollars each.​
pshichka [43]
Refraise the question
7 0
3 years ago
Read 2 more answers
Please Help.
Gennadij [26K]
Answer:
amount of nuts = 2 pounds
amount of dried fruit = 4 pounds

Explanation:
We are given that x is the amount of nuts and y is the amount of dried fruit.
We are also given that:
1- Hunter needs to make 6 pounds of trail mix. This means that:
x + y = 6
This can be rewritten as:
x = 6 - y .........> equation I
2- x costs $4 per pound, y costs $3.5 and Hunter can spend a total of $22. This means that:
4x + 3.5y = 22 ..........> equation II

Substitute with equation I in equation II and solve for y as follows:
4x + 3.5y = 22
4(6-y) + 3.5y = 22
24 - 4y + 3.5y = 22
24-22 = 4y-3.5y
2 = 0.5y
y = 4 pounds

Substitute with y in equation I to get the value of x as follows:
x = 6-y
x = 6-4
x = 2 pounds

Hope this helps :)

7 0
3 years ago
PLS HELP I'LL GIVE BRAINLIEST
VashaNatasha [74]

Answer:

$5,000

Step-by-step explanation:

Create a proportion:

11/100 = 550/x

100(550)/11

5,000= x

5 0
3 years ago
Read 2 more answers
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