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aleksley [76]
3 years ago
13

Please Help me!!! with this problem

Mathematics
1 answer:
dimaraw [331]3 years ago
8 0

9514 1404 393

Answer:

  D  120

Step-by-step explanation:

We are given the relation ...

  48 = 0.40 × sales

Dividing by 0.40 gives the sales for the day.

  sales = 48/0.40 = 120

120 milkshakes were sold that day.

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Ms. Cohen is buying supplies for her kindergarten class room. she can spend at most $30. she wants to buy boxes of crayons that
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15

Step-by-step explanation:

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3 years ago
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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf
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Answer:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We have the following data given:

\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by \alpha=1-0.93=0.07 and \alpha/2 =0.035. And the critical value would be given by:  

z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811  

The confidence interval is given by:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

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You are given a problem that involves multiplying a positive number and a negative number. Which of the following are reasonable
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First question:. A and D. Second question: B and C .
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Find each unit price which is the better buy explain electrical wire $1.89 for 3 ft 89 for 18 in
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Answer:

It all comes down to simplifying it to inches and price so id 18 in” is 0.89 cent’s thats every inch of that 18 is about 4 cents a in” and a $1.89 3 feet is about 5 cent’s

Step-by-step explanation:

So is the first would be a better deal because it is one cent cheaper!

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Plan B or plan D will be the fastest.
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