Answer:
Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have
substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)
Answer:
It is pi over nine, the one that your cursor is on. Forgive me if I am wrong
Step-by-step explanation:
Answer:
5.1
Step-by-step explanation:
-44.288-31.6 / -3.1(6-1.2)
Add -44.288 and -31.6
= -75.888 / -3.1(6-1.2)
Subtract 1.2 from 6
= -75.888 / -3.1(4.8)
Multiply -3.1 and 4.8
= -75.888 / -14.88
Divide -75.888 by -14.88
-75.888 / -14.88
=5.1
Answer: 68
Explanation:
Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children
We can write:
(x + y + a + b + c)/5 = 38
But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54
Substitute this value to our first equation
(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136
Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2
But x + y = 136
=> mean age = 136/2 = 68
