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3 years ago

XA

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

8 0

Answer

D is the correct answer.

Reason

it is so because rectangle has adjacent perpendicular parallel sides with opposite sides equal

sveticcg [70]3 years ago

3 0

The answer is C. No, the adjacent sides are not perpendicular.

<h2>Hope ths helps</h2><h2></h2><h2>From Cambridge</h2>

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Factor the expression 77x + 21

klemol [59]

Answer:   7(11x + 3) .
______________________________________________________
Explanation:
______________________________________________________
We are asked to: "Factor the expression: 77x + 21 ."
______________________________________________________
Upon examination of <u>both</u>: "<u><em>77x</em></u>" and "<u><em>21</em></u>" ; we can see that "<u><em>7</em></u>" is the greatest common factor (GCF) of BOTH. We can examine this visually, but let us write this out:
_______________________________________________________
21: 1, 3, <em><u>7</u></em>, 21

77x ;
or simply: 77: 1, <u><em>7</em></u>, 11, 77
_____________________________
So, to proceed:
_____________________________
Write down a: "7" ;
_______________________________
7 *( ????)
________________________________
Note the distributive property of multiplication:
______________________________________
a(b+c) = ab + ac ; AND:

a(b - c) = ab - ac ;
____________________________________________________
So , we write down a "7" ;
____________________________________________________
7*( ???
____________________________________________________
The first value is: "+77x" ; so, " 7 * ? = 77x ?" ;

We can examine this visually and realize that the value is "11x";

or we can divide, as follows: (77x/ 7 = 11x ).
___________________________________________
So we have already written down: 7* (??? )
________________________________________
We can down rewrite as: " 7 * (11x ......)
________________________________________
(since " 7 * 11x = 77x ") ;
_____________________________________
The next (and in our case, final !) value in our expression is:
__________________________________________________
" +21 " ;
__________________________________________________
We have written down: 7* (11x ......)
__________________________________________________
So now, we need to determine: "7 * ? = 21" ?
__________________________________________________
We can inspect visually and determine the value is: "3" ;
__________________________________________________
Or we can solve by division, as follows:
__________________________________________________
"7 * ? = 21 ?" ; 21 / 7 = ? ; 21 / 7 = 3 . The value is: "3" .
__________________________________________________
So , we have: " 7 * (11x .....) " ; now we can rewrite as:
____________________________________________________________
" 7*(11x + 3)" ; or, simply: " 7(11x +3)" ; The multiplication is implied).
_________________________________________________________
The answer is:   7(11x +3) .
_______________________________________
Does our answer make sense? Let us check!

The answer; " 7(11x +3) " is the factored expression of: "(77x + 21)" ;
__________________________________________________
So: " 7(11x +3) " should EQUAL "77x +21 " . Is this true??
___________________________________________________________

Remember the distributive property of multiplication:
________________________________________________________
a(b+c) = ab +ac ;
________________________________________________________
So; " 7(11x +3) " = (7*11x) + (7*3) ; which equals:
_______________________________________________
  77x + 21 .   Yes!
________________________________________________________

8 0

3 years ago

I dont know this one either

Sergio039 [100]

The denominator is 20. If you multiply 10 by 2 and then divide it by 1 you will get the answer. This works with almost all fractions as long as there exists an equal sign in-between them.

5 0

3 years ago

How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit

Kisachek [45]

$\sqrt{x-8}$ is undefined if the argument $x-8$ is negative, so you first need to require that

$x-8\ge0\implies x\ge8$

We're not done yet, though, because $\dfrac1{\sqrt{x-8}}$ still doesn't exist when $x=8$ , so we remove this from the domain and we're left with $x>8$ , or in interval notation, $(8,\infty)$

To find the range, consider the limits of the function as you approach either endpoint of the domain.

$\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty$
$\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0$

Since $\dfrac1{\sqrt{x-8}}$ is positive everywhere, the range is $(0,\infty)$

3 0

3 years ago

There are 8 girls and 5 boys on the math team. Which ratio correctly describes the relationship between boys and girls on

ankoles [38]

Answer:

For every 5 boys there are 8 girls.

8 0

3 years ago

Read 2 more answers

A parallelogram has an area of x2+ 9x− 36.

Serhud [2]

Answer:

a) Length $x + 12$ , Width $x - 3$ , b) $x = 3$

Step-by-step explanation:

a) The expressions for the length and width of the parallelogram can be determined by factorizing the polynomial:

$A = x^{2} + 9\cdot x - 36$

$A = (x+12)\cdot (x-3)$

Length

$x + 12$

Width

$x - 3$

b) Since area is a positive variable, the set of solutions encompass all values of x such that area is zero o greater. Then, there are two interval where A is positive:

- When both binomials are negative.

$x \leq 3$ and $x \leq -12$

$x \leq -12$

- When both binomials are positive.

$x \geq 3$ and $x \geq -12$

$x \geq 3$

Since x is an integer, x must be positive and therefore the least possible value of x is:

$x = 3$

6 0

4 years ago