A=(-6,-2)
B=(6,2)
![\sqrt{[(6-(-6)]^2+[(2-(-2)]^2} = \sqrt{12^2+4^2} = \sqrt{16} =4 \sqrt{10}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%286-%28-6%29%5D%5E2%2B%5B%282-%28-2%29%5D%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%2B4%5E2%7D%20%3D%20%5Csqrt%7B16%7D%20%3D4%20%5Csqrt%7B10%7D%20)
B=(6,2)
What is 14.62 to the nearest whole number
2 answers:
You might be interested in
What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.
so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.
so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2