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3 years ago

Sixth grade

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

The answer is 12n + 3

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Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is repres

fredd [130]

Answer: D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

Step-by-step explanation:

Given : Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is represented by the function,

$A(t) = 5 + (0.25t)^3$

The number of bacteria of species B, B(t), after t hours is represented by the function, $B(t) = 2 + 8(1.06)^t$

Then, the difference in the number of bacteria, N(t), of both the species after t hours will be :-

$N(t)=A(t)-B(t)\\\\=5 + (0.25t)^3-(2 + 8(1.06)^t)\\\\=5 + (0.25t)^3-2-8(1.06)^t\\\\=5-2 +(0.25t)^3-8(1.06)^t\\\\=3+(0.25t)^3-8(1.06)^t$

Hence, the correct answer should be : D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

7 0

3 years ago

What is the probability that the web site has between 3 million and 4 million visitors in a single day? If needed, round your an

faust18 [17]

Answer:

0.2196

Step-by-step explanation:

Given that

Mean = 4.56 million visitors per day

Standard deviation = 820,000 visitors per day

According to the given situation the calculation of probability is shown below:-

Here we will find the value of P (3 ≤ X ≤ 4)

$P 93\leq X\leq 4)=P(X\leq 4) - P(X\leq 3)$

$\\=P(\frac{X-\mu}{\sigma}\leq \frac{4-4.56}{0.82})-P(\frac{X-\mu}{\sigma}\leq \frac{3-4.56}{0.82})$

$\\=P(Z\leq -0.683)-P(Z\leq -1.9024$

= 0.2483 - 0.0287

= 0.2196

Therefore the probability that the web site has between 3 million and 4 million visitors in a single day is 0.2196

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3 years ago

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Bingel [31]

Answer:

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r-ruslan [8.4K]

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