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Lana71 [14]
3 years ago
10

Mini made a recipe that yields 4 and 1 over 2 cups. If each serving is 1 over 2 cup, which expression will help Mini determine t

he number of servings her recipe will yield?
Mathematics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

1/2x = 4 1/2

Where x = Number of servings = 9 servings

Step-by-step explanation:

Mini made a recipe that yields 4 and 1 over 2 cups.

1 recipe = 4 1/2 cups

1 serving = 1/2 cups

1/2 cups = 1 servings

4 1/2 cups = x servings

Cross Multiply

1/2 × x = 4 1/2

x = 4 1/2 ÷ 1/2

x = 9/2 ÷ 1/2

x = 9/2 × 2

x = 9 servings.

Therefore, the expression tha will help Mini to determine the number of servings her recipe will yield is

1/2x = 4 1/2

Where x = Number of servings = 9 servings

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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

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The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

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