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Sedaia [141]
3 years ago
11

John is driving on a highway.He uses one gallon of gas every 25 miles he drives.The distanc, D (in miles), he travels on g gallo

ns of gas is given by the following. How far does John drive if he uses 2 gallons of gas
Mathematics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

I need help on this thing too someone help

Step-by-step explanation:

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What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
4 0
4 years ago
Fill the table using this function rule.
ElenaW [278]
Y=29-2(1)
y=29-2=27
(1,27)
y=29-2(3)
y=29-6=23
(3,23)
y=29-2(4)
y=29-8=21
(4,21)
y=29-2(5)
y=29-10=19
(5,19)
7 0
3 years ago
What is the value of x?<br><br> 3<br> 4<br> 6<br> 8
bekas [8.4K]
The longer sides of the rectangles should be the same value, so we can make the lower part of the equation equal to 18, which is 4.
We can even find the y value by making it equal to 10, which is 3.
8 0
4 years ago
Read 2 more answers
A town has a population of 5000 and grows at 4% every year. What will be the population after 7 years, to the nearest whole numb
Rudiy27

I think this is.. ↓

grows 4% at every year

after 7 years ↓↓

4 × 7 = 28

A town has a population of 5000

28% of 5000 = 1400

5000 + 1400 = 6400


after 7 years, town has 6400 population = after 7 year grows 28%

7 0
3 years ago
Read 2 more answers
Jacob consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Jacob's body
sasho [114]

Answer: 0.87400mg of caffeine.

Step-by-step explanation:

You have

N(t)=N0(e^−rt)(1)

as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,

N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)

Taking the last 2 parts of (2) to the power of 0.1t gives

e^−rt=0.2601^.1t . .(3)

This means that

N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)

Also,

N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1

= 0.87400mg of caffeine.

6 0
3 years ago
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