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1 year ago

Is this statement true or false?

Mathematics

2 answers:

Galina-37 [17]1 year ago

6 0

Answer:

True

Step-by-step explanation:

Renters probably aren't going to rent to you if you have a poor credit history.

hope this helps, brainliest appreciated!

kap26 [50]1 year ago

3 0

Answer:

true

Step-by-step explanation:

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Curtis threw 15 darts at a dartboard . 40 percent of his darts hit the bull's eye. how many darts did not hit the bull's eye

PIT_PIT [208]

40%=0.4
15*0.4
6
15-6
9 darts didn't hit the bull's eye

7 0

2 years ago

Use the slope formula to find the missing coordinate: R(0,_), S(-4,2) m=5

Delicious77 [7]

Answer

The missing value is 22

step-by-step explanation

The slope formula is

$m = \frac{y_2 - y_1}{x_2 - x_1}$

From the question,

m=5

$x_2=-4$

$y_2=2$

and

$x_1=0$

We substitute these values to get,

$5= \frac{2 - y_1}{ - 4- 0}$

Simplify

$5= \frac{2 - y_1}{ - 4}$

$5 \times - 4=2 - y_1$

$- 20=2 - y_1$

$- 20 - 2=- y_1$

$22= y_1$

$y_1 = 22$

The missing value is 22

5 0

2 years ago

HELP ASAP WILL GIVE 15 POINTS!!!

sladkih [1.3K]

Answer:

Step-by-step explanation:

Since its changing the y, we now it has to be outside the x. So its not A or D. Since it moves up, its a plus. This means its not c, so it has to be B.

5 0

2 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

2 years ago

Write and solve a real-world problem involving the multiplication of a fraction and a whole number whose productis between 10 an

Andreyy89

You have to make a problem that could happen in the real world that multiplication of a fracton using product between 10 and 15

4 0

2 years ago